(2x+5)(5x^2-26x+5)=0

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Solution for (2x+5)(5x^2-26x+5)=0 equation: 


Simplifying
(2x + 5)(5x2 + -26x + 5) = 0

Reorder the terms:
(5 + 2x)(5x2 + -26x + 5) = 0

Reorder the terms:
(5 + 2x)(5 + -26x + 5x2) = 0

Multiply (5 + 2x) * (5 + -26x + 5x2)
(5(5 + -26x + 5x2) + 2x * (5 + -26x + 5x2)) = 0
((5 * 5 + -26x * 5 + 5x2 * 5) + 2x * (5 + -26x + 5x2)) = 0
((25 + -130x + 25x2) + 2x * (5 + -26x + 5x2)) = 0
(25 + -130x + 25x2 + (5 * 2x + -26x * 2x + 5x2 * 2x)) = 0
(25 + -130x + 25x2 + (10x + -52x2 + 10x3)) = 0

Reorder the terms:
(25 + -130x + 10x + 25x2 + -52x2 + 10x3) = 0

Combine like terms: -130x + 10x = -120x
(25 + -120x + 25x2 + -52x2 + 10x3) = 0

Combine like terms: 25x2 + -52x2 = -27x2
(25 + -120x + -27x2 + 10x3) = 0

Solving
25 + -120x + -27x2 + 10x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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